"Isoelectronic molecules and ions have identical bond orders." Explain by examples.
Bond order in Isoelectronic molecules/ions :
If two or more diatomic molecule or ion are isoelectronic so its bond order is same. Example-$1$: $\mathrm{F}_{2}$ and $\mathrm{O}_{2}^{-2}$ both have same $18$ electrons and bond order is also same $1$ . $\mathrm{F}_{2}: \mathrm{F}-\mathrm{F}$ and $\mathrm{O}_{2}^{-2}(\mathrm{O}-\mathrm{O})^{2-}$
Example-$2$: $\mathrm{N}_{2}, \mathrm{CO}$ and $\mathrm{NO}^{+}$are isoelectronic and containing $14$ electron and triple bond in it.
Molecule/ion | $\mathrm{N}_{2}$ | $\mathrm{CO}$ | $\mathrm{NO}^{+}$ |
Bond structure | $\mathrm{N} \equiv \mathrm{N}$ | $\mathrm{C} \equiv \mathrm{O}$ | $\mathrm{N} \equiv \mathrm{O}^{+}$ |
Maximum unpaired electrons are present in
State resemblance and differentence - both sigma and pai bond
In which of the following transformations, the bond order has increased and the magnetic behaviour has changed ?
Bond energies in $NO,\,N{O^ + }$ and $N{O^ - }$ are such as
Incorrect statement when $C_2$ change to $C_2^{-2}$